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santosh1984
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Posted on 12-06-09 11:31
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Your dimensions are right. (A-A1) is a 4x4 matrix and B1 is a 4x2 matrix which implies your Am matrix is 2x4.
I just tried it in matlab. Type this in your program or command window after defining the matrices A, B1, A1;
Am=B1\(A-A1); remember it's \ not /
However, Am is coming out to be a zero matrix. I don't know if that is right. Solution from matlab:
A =
0 1.0000 0 -0.0001 7.5781 21.2169 -2.4152 -6.1767 0 -0.0004 0 1.0001 27.2402 78.6220 -8.6725 -22.9705
A1 =
0 1.0000 0 0 7.5781 21.2169 -2.4152 -6.1767 0 0 0 1.0000 27.2402 78.6220 -8.6725 -22.9705
B1 =
0 0 1.0000 0.0022 0 0 0 1.0000
Am =
0 0 0 0 0 0 0 0
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birajasharma
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Posted on 12-07-09 1:59
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Thank you Santosh.It was great help.
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truthspeaker
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Posted on 12-07-09 4:00
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Keep it up guys, it's a good thread. Jaach ma chai malai yeso dekhau hai......bro haru
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BostonKtm
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Posted on 12-07-09 2:44
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cheers for the guy like santosh 1984.. guys like you are new hope for sajha.....Nepal ta kaaataam bhayooo ghou....
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GuitarDaku
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Posted on 12-07-09 3:59
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If Am = 0 then A = A1. Clearly that is not true. Look at A(2,3) = -0.0004 and A1(2,3) = 0. Small difference, I suppose. I wonder if this is more subtle?
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