A doctor in Michigan has a sister who lives in California but the sister does not have any brother that lives in Michigan, how come??
:P

Nicely done, hetterika.

Another one:

There is a big, perfectly round table. You and I each have a heap of quarters (let's say unlimited amount to avoid any confusion). Each of us have to take turns placing one quarter on the table. The person who places the last coin (when there is no space left anywhere on the table), wins the game.

How would you ensure that you win the game?

What is the comment for this?

1 = 1

=> 1^1 = 1^0

=> 1 = 0

Let the other guy place the first quarter?

republican,
Is it you calculate the serface area of table and coin. divide the surface area of the table by the surface area of the coin. if the answer is odd number I start if first and if the answer is even number let the other person start first. Is this the solution?? I am confused coz there will be some spaces unused inbetween.

Pretty, you could be right, but the answer is a little more specific : )

ritthe, the size of the table and coin is unknown, the solution would be applicable to any table size.

preety could be wrong. what if the size of the table is equal to the size of the coin, other person will win in first move.

we can calculate the area by measuring the diameter of coin and table. What is the solution then if we don't know the area????

this is logical more than mathematical.. also let's not assume that the size of a table could be the same as the size of a quarter! we're making reasonable assumptions here..a table that is perfectly round and perfectly round coins..eg quarters.

hint: you've already taken the first step to the solution by explaining how preety could be wrong.

republic, I think it always takes odd number of smaller circles to cover bigger circle, like, 1, 3, 5. So we should start first to win. Is it the answer??? I am not sure though ......

i am wrong ...... republic I give up ...... give me the answer coz I am at work and don't want to be thinking abt it all the time ..........hehe

You got the first part right. You have to start first to win. The answer is more specific, because you're playing against another person and you need a foolproof strategy to ensure that you win.

I'll let you torture yourself some more : ) and maybe somebody else might wanna give it a try.

The person who places the last coin (when there is no space left anywhere on the table), wins the game.

so be the last person to place the coin (wait everybody to have their coins placed and take a chance to place your coin as soon as you see there is just a single space to place your coin)

and I WIN!!!!!!!!!!!!

but coins over the bigger circle never occupies a complete space on the circle (lets say table)
there will be atleast some space available on the table though not to fit the coin in.


The person who places the last coin (when there is no space left anywhere on the table), wins the game. this might create another confusion because how can you place a coin on the table when there is no space
so be the last one to put the last coin over the heap on the table.


JPT try

you have to put the first coin in the middle so that, it will always take odd number of coins to cover the table ....... i got it this time

republican, this is ritthe_jasus. Is my logic correct or not???? Damn you sure know how to torture people. hello ....... waiting for answer.

"Since they were told to raise the hand when they see red, X and Y had red and Z had black, X realised he had red cap because Y was raising hand when Z had black cap, he was the one left with red cap which Y saw."

Correct, Ritthe_jasus!

Ok, now what if all of them had red caps, how'd x find he is wearing red cap? Same scenarion, only this time all of them with red caps. Dare it? :P

Okay, here's the question to all who are interested:

There are three people and they are blindfolded. Now, they are given one cap each, all of them are given red caps, which they wear, unware what color it is. However, they are told that either they either have a black cap or a red cap and they can see two other's cap once the blindfold is removed. Also, they are told that once the blindfold is removed, and if they see any red cap, they will have raise their hand.

Now they open their eyes. One can't see what one is wearing, but can see two other's cap. One of the people their would be able to tell "I am wearing red cap!" logically. How?

Republican, I tried to figure out if I could answer your question, but I give up! Like Ritthe said, you are tortoring us; we demand the answer! ;) :D

i demand answe from you too slackdemic ....... hehehe ...... how do you know you have red cap ...... is that like shooting in the dark ... lol ;-))

hehe, well, with little more "torture" to your brain, maybe it will help you get it. Same logic, that you applied for 2 red and 1 black caps/cap, applies to this as well, but way too complicated than the former one. Try if you want.

Not going to give answer this early! :P :D

damn ok i will wait for slackdemic ........ but republic what happened to the answer ....... first move have to be to put coin at the center of the table, coz it always take odd number of coins to fill the whole round table if you put the first one at the center.