Dear Sajhaities,

I hope here are some mathmatician.
One of my friends asked me one question that it is true:

2+2 = 22

Could someone explain me how is it true?

Com'on guys!
I have given 2 solutions for the problem... u guys still discussing the same thing.

I dont know if u guys understood the solution.

And by the way.. 2+2 = 22 ..doesn't work in any base.. so no point in trying out bases.
It can only be done if u have a coding system which codes such that binary value of 2 + 2 as 22.
by the way- freek..its 2 + 2 =22 .. its not that 2 2 =22
- for confused - if it would be in base 10 ( which is used in everyday life).. nobody have raised the query.... its 2 2 = 22 in base 10 considering these are two bits... but here the problem is 2+2 = 22....

Gaalabian Algebra

It's based on trianary system (0, 1, 2)

Let me explain with an example....

Let's divide the Nepalese society into three classes. When a couple get married, the person in the lower rank will take the status of higher class as well (suerely, mahila-purush barabri theory lagu hunchha) . That would mean,

Middle-Class + Upper-Class = Upper-Class Upper-Class
Middle-Class + Middle-Class = Middle-Class Middle-Class
Upper-Class + Working Class = Upper-Class Upper-Class

Let's represent Working Class, Middle Class and Upper Class as 0, 1, 2

The Gaalabian Algebra will, thus, give the following result
0 + 0 = 00
0 + 1 = 11
0 + 2 = 22
1 + 0 = 11
1 + 1 = 11
1 + 2 = 22
2 + 0 = 22
2 + 1 = 22
2 + 2 = 22

Dear all,
Mmany thanx for your explanations.

I have one solution which goes as follows:
Lets suppose in Foral Numbering system where we have only 0, 1, 2 & 3.

LHS
=22
=2*4^1+2*4^0 (Converting in Foral numbering system)
=10
=1*4^1+0*4^0 (Converting in Foral numbering system)
=4
=2+2
=RHS

I hope this is one of the many solutions.

Kiwiland, I think yours is the only answer close to right. But then, you could code it to whatever you want, that way anything can be proven right.

Sarala, I am not sure if you already know your assesment is wrong or not, but neverthless, pardon my explanation:

Note the comment after the dots.

LHS
=22 .........given
=2*4^1+2*4^0 (Converting in Foral numbering system) .....okay so far.
=10 .......... agree, that's the decimal representation of 22.
=1*4^1+0*4^0 (Converting in Foral numbering system) .........now wait a minute!!! what are you doing? Here u are converting 10 to decimal as if 10 was a foral already. Remember it never was foral as in above operation, you actually converted foral to decimal. End of story.

=4 .........u will never get this far. Instead of converting 10 to foral, the only thing that is allowed is finding the foral representation of 10.
=2+2
=RHS


It should be a waste of time to try to find a way to fix this equation.
I'd go with Kiwiland's answer.

Technically when you add in binary...1+1 =11...and one of em will be carry one.

Ok folks, this is the way you do it!!!

88 = 88
or, -88 = -88
or, 16 - 4 * 26 = 484 - 22 * 26
or, 4^2 - 4 * 26 = 22^2 - 22 * 26
or, 4^2 - 2 * 4 * 13 = 22^2 - 2 * 22 * 13

Adding to both sides the term: 13^2

or, 4^2 - 2 * 4 * 13 + 13^2 = 22^2 - 2 * 22 * 13 + 13^2

both LHS and RHS correspond to (a^2 - 2ab + b^2 = (a-b)^2 )
so, (4-13)^2 = (22-13)^2
Taking square root of both,
4-13 = 22-13
Accepting your say that 2 + 2 = 4 in LHS,
2 + 2 -13 = 22 - 13
therefore,
2 + 2 = 22

Kasto lagyo mulaharu?

haha, keta haru ni...

DWI, ooh maan...yah i also figured later that it wasnt correct..suxxx and i agree on what you said...


kiwi bro, u got the answer ..hurray!!

username, i dont know what u did...arent we proving 2+2 = 22, not 88 = 88...khoi i must be lost..


btw, here's logarithmic differentiation problem, can anyone help me with it..

y = (x^2x(x-1)^3)/(3+5x)^4

you could say that it works for Z₂
2≡0 mod 2, so 2 + 2 = 0 ≡2 mod 2

make that 2 + 2 = 0 ≡ 22 mod 2

heres one that used to confuse me a lot, until i figured out the error

x² = x + x + x + ...... +x (x times)

taking the derivative wrt x on both sides,

2x = 1 + 1 + 1 + .... + 1 (x times)

2x=x

2=1



simple, and confusing

how is this possible?

Confused?s problem:

If I understood your question correctly, and your question is y = (x^ (2x ) (x-1)^3)/(3+5x)^4, and you want to find the derivative of that function, the answer is:


y? = [{(x-1) ^2. x^ (2x)} {5x-29-2(3+5x)(x-1).ln(x+1)}}] / [ (3+5x) ^ 5]

It?s bit long though.
Too lazy to show all the work.

HEHE !!

username le sarahi hasayo yaar.. tyasto bacha buchi trick lagayera bho ta la
**** both LHS and RHS correspond to (a^2 - 2ab + b^2 = (a-b)^2 )
so, (4-13)^2 = (22-13)^2
Taking square root of both,
4-13 = 22-13 ****

yo ta tyaho baccha bucchi lai -1 =+1 prove garera almalyaune trick nai bho ni...
When u take square root of something... how can u forget that its always + and -.
that proves... 9 =9 and and -9=-9. now can u say -9=+9.????
So Username is also wrong!! hehe..

I am saying u guys .. no point in trying using the existing numbering system... u need to develop new coding system for that..hehe

Sarala's answer was also ridiculous.. thanks DWI for clarifying where c was wrong...

Confuse, U SUCK

Thatz not the solution, aani where did that "absolute value" came from?

Bro, i said Prove: (+1) = (-1)

So, prove, and bro be specific and give while u prove.

Anywayz, any one who can prove (+1) = (-1)



*The solution will b up here*


*************************
Pease Out

le chef du nuit,

It seems x is an integer.
You can't take derivative for such x.

My Question:
Boy: May I ask your name?
Girl: See the number plate of my Car.
Boys goes to see it it was 32-11.
What's her name? (Note: It's in Nepal.)

anybody who has had preliminary education in modular arithmetic(or number theory) won't find it difficult to notice the congruencies:
2+2 = 22 (mod 18)
and
1+1=11 (mod 9)

Hey muji, khupi chha bhane prove garera dekha haina bhane nakara.

no way dont tell me you are going to take square root of of both 1's :P

babu, maile timilai suck ra fk bhaneko ta chaina ni, kina testo matteko :)

by the way, absolute value of -1 and 1 is equal to 1 :)

Confused Bro,
Yes U R Dumbed.

1.The census checked the next door. Agree?

2.
36*1*1 (sum=38)
18*2*1 (sum=21)
9*4*1 (sum=14)
9*2*2 (sum=13)
6*6*1 (sum=13)
6*3*2 (sum=11)
4*3*3 (sum=10)
Agree?

3. If the sum(=address of next door) was 11 or 21 or 10 or 14 or 38, he doesn't have to be confused. But it must be 13 so that it made him confusion because the sum becomes 13 in 2 different caes as mentioned in 2.

4. Got it?

Explorer is absolutely right.

Dear all, thanks a lot!

May I put next question.

Question:
What is the dring we can get by the following substraction:

Half Circle Full Circle Half Circle A - Half Circle Full Circle Perpendicular A

HA HA @ confuse

By the way, confuse broda, u were right about the takin the square of 1's

m sorry for the lang. i used. U ROcK

Pease Out :(